What are the solutions to the equation 4x^2+10x+4=0 ?

The solutions to the equation 4x^2+10x+4=0 are x=-1/2 ,x=-2

Find the zeros of 4x^2+10x+4=0

The zeros of 4x^2+10x+4=0 are x=-1/2 ,x=-2

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4 x^{2} + 10 x + 4 = 0

x = - \frac{1}{2}, x = - 2

Solution steps

4 x^{2} + 10 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 4 \cdot 4}{2 \cdot 4}

1 0^{2} - 4 \cdot 4 \cdot 4 = 6

x_{1, 2} = \frac{- 10 \pm 6}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 10 + 6}{2 \cdot 4}, x_{2} = \frac{- 10 - 6}{2 \cdot 4}

x = \frac{- 10 + 6}{2 \cdot 4} : - \frac{1}{2}

x = \frac{- 10 - 6}{2 \cdot 4} : - 2

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = - 2

j^{2} - 5 j - 14

3 x + 5 = 2

\frac{- 7}{- 2}

2 (8 x - 4) - 2 x \leq 14 x + 12

\frac{( - 35 x y ) ^{4}}{( 14 x yz ) ^{4}}

What are the solutions to the equation 4x^2+10x+4=0 ?
The solutions to the equation 4x^2+10x+4=0 are x=-1/2 ,x=-2
Find the zeros of 4x^2+10x+4=0
The zeros of 4x^2+10x+4=0 are x=-1/2 ,x=-2