What is factor 1+8t^3 ?

The solution to factor 1+8t^3 is (2t+1)(4t^2-2t+1)

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factor 1+8t^3

factor

1 + 8 t^{3}

(2 t + 1) (4 t^{2} - 2 t + 1)

Solution steps

1 + 8 t^{3}

Write in the standard form

= 8 t^{3} + 1

Apply exponent rules

= (2 t)^{3} + 1^{3}

Apply Sum of Cubes Formula:

x^{3} + y^{3} = (x + y) (x^{2} - x y + y^{2})

(2 t)^{3} + 1^{3} = (2 t + 1) (2^{2} t^{2} - 2 t + 1)

= (2 t + 1) (2^{2} t^{2} - 2 t + 1)

2^{2} = 4

= (2 t + 1) (4 t^{2} - 2 t + 1)

(x^{\frac{5}{6}}) (x^{\frac{1}{3}})

2 (- 1) + 1

(\frac{1}{x ^{2} - 4 x - 5})^{\frac{1}{2}}

4 x^{2} + x - 18 = 0

0.4 (u e^{- 4})^{2} = 0.2 (\frac{u e ^{- 4} - u}{4})