What is the answer to 2x^{-2}-3x^{-1}-2=0 ?

The answer to 2x^{-2}-3x^{-1}-2=0 is x=-2,x= 1/2

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2x^{-2}-3x^{-1}-2=0

2 x^{- 2} - 3 x^{- 1} - 2 = 0

x = - 2, x = \frac{1}{2}

Decimal Notation

x = - 2, x = 0.5

Solution steps

2 x^{- 2} - 3 x^{- 1} - 2 = 0

Refine

\frac{2}{x ^{2}} - \frac{3}{x} - 2 = 0

Multiply by LCM

2 - 3 x - 2 x^{2} = 0

Solve

2 - 3 x - 2 x^{2} = 0 : x = - 2, x = \frac{1}{2}

x = - 2, x = \frac{1}{2}

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = - 2, x = \frac{1}{2}

x = \frac{1}{x}

\frac{1}{4 - x} + \frac{3}{6 + x} = 0

\frac{2}{x} = \frac{5}{4 x} + 3

x^{- 2} - x^{- 1} - 20 = 0

\frac{x + 7}{x - 2} = \frac{2}{9}

What is the answer to 2x^{-2}-3x^{-1}-2=0 ?
The answer to 2x^{-2}-3x^{-1}-2=0 is x=-2,x= 1/2
Solve for x: 2x^{-2}-3x^{-1}-2=0
The solution is x=-2,x= 1/2