What are the solutions to the equation 2y^2=4+y^2 ?

The solutions to the equation 2y^2=4+y^2 are y=2,y=-2

Find the zeros of 2y^2=4+y^2

The zeros of 2y^2=4+y^2 are y=2,y=-2

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2 y^{2} = 4 + y^{2}

y = 2, y = - 2

Solution steps

2 y^{2} = 4 + y^{2}

Move

y^{2}

to the left side

y^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = 4, y = - 4

4 = 2

- 4 = - 2

y = 2, y = - 2

8 x = 2 (x + 6)

5 x^{2} + 16 x + 3 = 5 x

7 ∣ 3 - p ∣ \leq - 14

6 x^{2} + 18 x - 60 = - 72

3 x - 15 \leq 10

What are the solutions to the equation 2y^2=4+y^2 ?
The solutions to the equation 2y^2=4+y^2 are y=2,y=-2
Find the zeros of 2y^2=4+y^2
The zeros of 2y^2=4+y^2 are y=2,y=-2