What are the solutions to the equation 5x^2+16x+3=5x ?

The solutions to the equation 5x^2+16x+3=5x are x=(-11+sqrt(61))/(10),x=(-11-sqrt(61))/(10)

Find the zeros of 5x^2+16x+3=5x

The zeros of 5x^2+16x+3=5x are x=(-11+sqrt(61))/(10),x=(-11-sqrt(61))/(10)

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5 x^{2} + 16 x + 3 = 5 x

x = \frac{- 11 + 61}{10}, x = \frac{- 11 - 61}{10}

Solution steps

5 x^{2} + 16 x + 3 = 5 x

Move

5 x

to the left side

5 x^{2} + 11 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 5 \cdot 3}{2 \cdot 5}

1 1^{2} - 4 \cdot 5 \cdot 3 = 61

x_{1, 2} = \frac{- 11 \pm 61}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 11 + 61}{2 \cdot 5}, x_{2} = \frac{- 11 - 61}{2 \cdot 5}

x = \frac{- 11 + 61}{2 \cdot 5} : \frac{- 11 + 61}{10}

x = \frac{- 11 - 61}{2 \cdot 5} : \frac{- 11 - 61}{10}

The solutions to the quadratic equation are:

x = \frac{- 11 + 61}{10}, x = \frac{- 11 - 61}{10}

7 ∣ 3 - p ∣ \leq - 14

6 x^{2} + 18 x - 60 = - 72

3 x - 15 \leq 10

x^{2} - 2 x + 2 = 0 - 576

(6 x^{2} y^{2})^{2}

What are the solutions to the equation 5x^2+16x+3=5x ?
The solutions to the equation 5x^2+16x+3=5x are x=(-11+sqrt(61))/(10),x=(-11-sqrt(61))/(10)
Find the zeros of 5x^2+16x+3=5x
The zeros of 5x^2+16x+3=5x are x=(-11+sqrt(61))/(10),x=(-11-sqrt(61))/(10)