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Popular >

x^2+8x>=-12

Solution

x^{2} + 8 x \geq - 12

Solution

x \leq - 6 or x \geq - 2

+1

Interval Notation

(- \infty, - 6] \cup [- 2, \infty)

Solution steps

x^{2} + 8 x \geq - 12

Rewrite in standard form

x^{2} + 8 x + 12 \geq 0

Factor

x^{2} + 8 x + 12 : (x + 2) (x + 6)

(x + 2) (x + 6) \geq 0

Identify the intervals

x \leq - 6 or x \geq - 2

Popular Examples

8 u^{2} + 8 u + 2 = 0

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\frac{16 a ^{4} + 16 a}{a ^{2} + 1 - a}

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(\frac{109}{50}) (\frac{157}{100})

simplify sqrt(64/4)simplify

\frac{64}{4}

factor k^4+8k^3+16k^2 factor

k^{4} + 8 k^{3} + 16 k^{2}

Frequently Asked Questions (FAQ)

What is x^2+8x>=-12 ?
The solution to x^2+8x>=-12 is x<=-6\lor x>=-2