What is the answer to (x-1}{x+1}=\frac{-6)/x ?

The answer to (x-1}{x+1}=\frac{-6)/x is x=-2,x=-3

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(x-1}{x+1}=\frac{-6)/x

\frac{x - 1}{x + 1} = \frac{- 6}{x}

x = - 2, x = - 3

Solution steps

\frac{x - 1}{x + 1} = \frac{- 6}{x}

Cross multiply

(x - 1) x = - (x + 1) \cdot 6

Solve

(x - 1) x = - (x + 1) \cdot 6 : x = - 2, x = - 3

x = - 2, x = - 3

Verify Solutions

Find undefined (singularity) points:

x = - 1, x = 0

Combine undefined points with solutions:

x = - 2, x = - 3

\frac{2 x}{2 x} = 2^{- 2 x}

\frac{14}{x} = x - 5

\frac{1}{2 b} + \frac{1}{b} = 2

\frac{8 ^{- 1}}{4 ^{- 1}} - a^{- 1} = 1

\frac{( 2 x - 3 ) ( x + 5 )}{x - 7} = 0

What is the answer to (x-1}{x+1}=\frac{-6)/x ?
The answer to (x-1}{x+1}=\frac{-6)/x is x=-2,x=-3
Solve for x: (x-1}{x+1}=\frac{-6)/x
The solution is x=-2,x=-3