What are the solutions to the equation x-3x^2=0 ?

The solutions to the equation x-3x^2=0 are x=0,x= 1/3

Find the zeros of x-3x^2=0

The zeros of x-3x^2=0 are x=0,x= 1/3

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x - 3 x^{2} = 0

x = 0, x = \frac{1}{3}

Solution steps

x - 3 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 3 x^{2} + x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 3 ) \cdot 0}{2 ( - 3 )}

1^{2} - 4 (- 3) \cdot 0 = 1

x_{1, 2} = \frac{- 1 \pm 1}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 1 + 1}{2 ( - 3 )}, x_{2} = \frac{- 1 - 1}{2 ( - 3 )}

x = \frac{- 1 + 1}{2 ( - 3 )} : 0

x = \frac{- 1 - 1}{2 ( - 3 )} : \frac{1}{3}

The solutions to the quadratic equation are:

x = 0, x = \frac{1}{3}

2 x + 2 \geq 6

t^{3} - 2 t^{2} - 23 t - 6

x^{2} + 2 x = 24

\frac{1}{∣ x + 3 ∣} > 5

m^{2} - 6 mn - 27 n^{2}

What are the solutions to the equation x-3x^2=0 ?
The solutions to the equation x-3x^2=0 are x=0,x= 1/3
Find the zeros of x-3x^2=0
The zeros of x-3x^2=0 are x=0,x= 1/3