What are the solutions to the equation x^2+2x=24 ?

The solutions to the equation x^2+2x=24 are x=4,x=-6

Find the zeros of x^2+2x=24

The zeros of x^2+2x=24 are x=4,x=-6

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x^{2} + 2 x = 24

x = 4, x = - 6

Solution steps

x^{2} + 2 x = 24

Move

24

to the left side

x^{2} + 2 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 24 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 24) = 10

x_{1, 2} = \frac{- 2 \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 10}{2 \cdot 1}, x_{2} = \frac{- 2 - 10}{2 \cdot 1}

x = \frac{- 2 + 10}{2 \cdot 1} : 4

x = \frac{- 2 - 10}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = 4, x = - 6

\frac{1}{∣ x + 3 ∣} > 5

m^{2} - 6 mn - 27 n^{2}

\frac{y}{3} + 6 = 9

∣ y - 5 ∣ = 3

- x^{2} + 12 x - 20 = 0

What are the solutions to the equation x^2+2x=24 ?
The solutions to the equation x^2+2x=24 are x=4,x=-6
Find the zeros of x^2+2x=24
The zeros of x^2+2x=24 are x=4,x=-6