What are the solutions to the equation x^2-6x+9=25 ?

The solutions to the equation x^2-6x+9=25 are x=8,x=-2

Find the zeros of x^2-6x+9=25

The zeros of x^2-6x+9=25 are x=8,x=-2

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x^{2} - 6 x + 9 = 25

x = 8, x = - 2

Solution steps

x^{2} - 6 x + 9 = 25

Move

25

to the left side

x^{2} - 6 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 16 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 16) = 10

x_{1, 2} = \frac{- ( - 6 ) \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 10}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 10}{2 \cdot 1}

x = \frac{- ( - 6 ) + 10}{2 \cdot 1} : 8

x = \frac{- ( - 6 ) - 10}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 8, x = - 2

6 (- \frac{1}{2})

(\frac{27}{8})^{- \frac{4}{3}}

- 3 ∣ x + 14 ∣ \geq - 9

4 (3 h - 11) \leq 6 (2 h - 3) + 19

1 x^{2} - 2 x - 1 = 0

What are the solutions to the equation x^2-6x+9=25 ?
The solutions to the equation x^2-6x+9=25 are x=8,x=-2
Find the zeros of x^2-6x+9=25
The zeros of x^2-6x+9=25 are x=8,x=-2