What is the answer to 5(2^x)=3(7^{4x-4}) ?

The answer to 5(2^x)=3(7^{4x-4}) is x=(4ln(7)+ln(5)-ln(3))/(4ln(7)-ln(2))

Solve for x: 5(2^x)=3(7^{4x-4})

The solution is x=(4ln(7)+ln(5)-ln(3))/(4ln(7)-ln(2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 (2^{x}) = 3 (7^{4 x - 4})

x = \frac{4 ln ( 7 ) + ln ( 5 ) - ln ( 3 )}{4 ln ( 7 ) - ln ( 2 )}

Decimal Notation

x = 1.16980 \dots

Solution steps

5 (2^{x}) = 3 (7^{4 x - 4})

Apply exponent rules

ln (5) + x ln (2) = ln (3) + (4 x - 4) ln (7)

Solve

ln (5) + x ln (2) = ln (3) + (4 x - 4) ln (7) : x = \frac{4 ln ( 7 ) + ln ( 5 ) - ln ( 3 )}{4 ln ( 7 ) - ln ( 2 )}

x = \frac{4 ln ( 7 ) + ln ( 5 ) - ln ( 3 )}{4 ln ( 7 ) - ln ( 2 )}

7 (2^{x}) = 2 (3^{4 x - 4})

4 (3^{x}) = 3 (6^{3 x - 3})

3^{3 x} = 7^{2 x + 1}

4^{x} = 8

2^{1 - x^{2}} = \frac{1}{8}

What is the answer to 5(2^x)=3(7^{4x-4}) ?
The answer to 5(2^x)=3(7^{4x-4}) is x=(4ln(7)+ln(5)-ln(3))/(4ln(7)-ln(2))
Solve for x: 5(2^x)=3(7^{4x-4})
The solution is x=(4ln(7)+ln(5)-ln(3))/(4ln(7)-ln(2))