What is the answer to 5^{2x}=20 ?

The answer to 5^{2x}=20 is x=(ln(20))/(2ln(5))

Solve for x: 5^{2x}=20

The solution is x=(ln(20))/(2ln(5))

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5^{2 x} = 20

x = \frac{ln ( 20 )}{2 ln ( 5 )}

Decimal Notation

x = 0.93067 \dots

Solution steps

5^{2 x} = 20

Apply exponent rules

2 x ln (5) = ln (20)

Solve

2 x ln (5) = ln (20) : x = \frac{ln ( 20 )}{2 ln ( 5 )}

x = \frac{ln ( 20 )}{2 ln ( 5 )}

4 - 3^{x} = 0

1 6^{2 x + 1} = 9^{3 x - 4}

1 6^{2 x - 3} 4^{- 2 x} = 16

13 e^{x} = 2 \cdot 3^{- x}

1 0^{x} = 3

What is the answer to 5^{2x}=20 ?
The answer to 5^{2x}=20 is x=(ln(20))/(2ln(5))
Solve for x: 5^{2x}=20
The solution is x=(ln(20))/(2ln(5))