What is the answer to 2^{2x}-9*2^x+8=0 ?

The answer to 2^{2x}-9*2^x+8=0 is x=3,x=0

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2^{2x}-9*2^x+8=0

2^{2 x} - 9 \cdot 2^{x} + 8 = 0

x = 3, x = 0

Solution steps

2^{2 x} - 9 \cdot 2^{x} + 8 = 0

Apply exponent rules

(2^{x})^{2} - 9 \cdot 2^{x} + 8 = 0

Rewrite the equation with

2^{x} = u

(u)^{2} - 9 u + 8 = 0

Solve

u^{2} - 9 u + 8 = 0 : u = 8, u = 1

u = 8, u = 1

Substitute back

u = 2^{x},

solve for

x

Solve

2^{x} = 8 : x = 3

Solve

2^{x} = 1 : x = 0

x = 3, x = 0

3^{x + 1} + 3^{x + 2} = 12

2^{x + 1} = 32

3^{1 - 7 x} = 8 1^{x - 2} \cdot 9^{2 x}

(\frac{1}{4})^{9 x - 5} = 3 2^{x + 8}

2 5^{3 x - 1} = 5

What is the answer to 2^{2x}-9*2^x+8=0 ?
The answer to 2^{2x}-9*2^x+8=0 is x=3,x=0
Solve for x: 2^{2x}-9*2^x+8=0
The solution is x=3,x=0