What is the answer to 3^{x+1}+3^{x+2}=12 ?

The answer to 3^{x+1}+3^{x+2}=12 is x=0

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3^{x+1}+3^{x+2}=12

3^{x + 1} + 3^{x + 2} = 12

x = 0

Solution steps

3^{x + 1} + 3^{x + 2} = 12

Factor

3^{x + 1} + 3^{x + 2} : 4 \cdot 3^{x + 1}

4 \cdot 3^{x + 1} = 12

Divide both sides by

4

3^{x + 1} = 3

Apply exponent rules

x + 1 = 1

Solve

x + 1 = 1 : x = 0

x = 0

2^{x + 1} = 32

3^{1 - 7 x} = 8 1^{x - 2} \cdot 9^{2 x}

(\frac{1}{4})^{9 x - 5} = 3 2^{x + 8}

2 5^{3 x - 1} = 5

9^{x + 2} = (\frac{1}{27})^{x - 3}

What is the answer to 3^{x+1}+3^{x+2}=12 ?
The answer to 3^{x+1}+3^{x+2}=12 is x=0
Solve for x: 3^{x+1}+3^{x+2}=12
The solution is x=0