What is the answer to 9^{(x+2)}=27^{(x+1)} ?

The answer to 9^{(x+2)}=27^{(x+1)} is x=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9^{(x+2)}=27^{(x+1)}

9^{(x + 2)} = 2 7^{(x + 1)}

x = 1

Solution steps

9^{(x + 2)} = 2 7^{(x + 1)}

Apply exponent rules

2 (x + 2) = 3 (x + 1)

Solve

2 (x + 2) = 3 (x + 1) : x = 1

x = 1

8^{3 x} = (\frac{1}{4})^{x + 1}

y, \frac{y}{e ^{x y}} = x

2^{5 x - 2} = 2^{x + 2}

2^{2 x + 7} = 2^{15}

3^{2 7^{x + 3}} = 2 7^{9^{x + 3}}

What is the answer to 9^{(x+2)}=27^{(x+1)} ?
The answer to 9^{(x+2)}=27^{(x+1)} is x=1
Solve for x: 9^{(x+2)}=27^{(x+1)}
The solution is x=1