What is the answer to 8^{3x}=(1/4)^{x+1} ?

The answer to 8^{3x}=(1/4)^{x+1} is x=-2/11

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8^{3x}=(1/4)^{x+1}

8^{3 x} = (\frac{1}{4})^{x + 1}

x = - \frac{2}{11}

Decimal Notation

x = - 0.18181 \dots

Solution steps

8^{3 x} = (\frac{1}{4})^{x + 1}

Apply exponent rules

9 x = - 2 (x + 1)

Solve

9 x = - 2 (x + 1) : x = - \frac{2}{11}

x = - \frac{2}{11}

y, \frac{y}{e ^{x y}} = x

2^{5 x - 2} = 2^{x + 2}

2^{2 x + 7} = 2^{15}

3^{2 7^{x + 3}} = 2 7^{9^{x + 3}}

3^{2 x - 1} = 17

What is the answer to 8^{3x}=(1/4)^{x+1} ?
The answer to 8^{3x}=(1/4)^{x+1} is x=-2/11
Solve for x: 8^{3x}=(1/4)^{x+1}
The solution is x=-2/11