What is the answer to 3^{27^{x+3}}=27^{9^{x+3}} ?

The answer to 3^{27^{x+3}}=27^{9^{x+3}} is x=-2

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3^{27^{x+3}}=27^{9^{x+3}}

3^{2 7^{x + 3}} = 2 7^{9^{x + 3}}

x = - 2

Solution steps

3^{2 7^{x + 3}} = 2 7^{9^{x + 3}}

Apply exponent rules

3 (x + 3) = 1 + 2 (x + 3)

Solve

3 (x + 3) = 1 + 2 (x + 3) : x = - 2

x = - 2

3^{2 x - 1} = 17

x, e^{7 - 4 x} = 6

2^{3 x + 5} = 6 4^{x - 7}

e^{2 x} - 8 e^{x} + 15 = 0

200 = 100 e^{r \cdot 6}

What is the answer to 3^{27^{x+3}}=27^{9^{x+3}} ?
The answer to 3^{27^{x+3}}=27^{9^{x+3}} is x=-2
Solve for x: 3^{27^{x+3}}=27^{9^{x+3}}
The solution is x=-2