What is the answer to sqrt(3^{2x+1)}=9^{x-2} ?

The answer to sqrt(3^{2x+1)}=9^{x-2} is x= 9/2

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sqrt(3^{2x+1)}=9^{x-2}

3^{2 x + 1} = 9^{x - 2}

x = \frac{9}{2}

Decimal Notation

x = 4.5

Solution steps

3^{2 x + 1} = 9^{x - 2}

Apply exponent rules

(2 x + 1) \frac{1}{2} = 2 (x - 2)

Solve

(2 x + 1) \frac{1}{2} = 2 (x - 2) : x = \frac{9}{2}

x = \frac{9}{2}

10 = 2^{x}

3 6^{(3 x - 1)} = 6^{(4 x + 2)}

(- e^{- k} + e^{\frac{- 5 k}{6}}) = 2

2^{2 x} = 16

(e^{4})^{x} e^{x^{2}} = e^{12}

What is the answer to sqrt(3^{2x+1)}=9^{x-2} ?
The answer to sqrt(3^{2x+1)}=9^{x-2} is x= 9/2
Solve for x: sqrt(3^{2x+1)}=9^{x-2}
The solution is x= 9/2