What is the answer to 8^{x+1}*2^{2x}=4^{3x-1} ?

The answer to 8^{x+1}*2^{2x}=4^{3x-1} is x=5

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8^{x+1}*2^{2x}=4^{3x-1}

8^{x + 1} \cdot 2^{2 x} = 4^{3 x - 1}

x = 5

Solution steps

8^{x + 1} \cdot 2^{2 x} = 4^{3 x - 1}

Apply exponent rules

3 (x + 1) + 2 x = 2 (3 x - 1)

Solve

3 (x + 1) + 2 x = 2 (3 x - 1) : x = 5

x = 5

3^{7 - 2 x} = (\frac{1}{27})^{- 8}

73 = 2 3^{x}

9^{x + 1} + 3 = 28 \cdot 3^{x}

4 9^{x} = 7

1 0^{x} + 5 = 60

What is the answer to 8^{x+1}*2^{2x}=4^{3x-1} ?
The answer to 8^{x+1}*2^{2x}=4^{3x-1} is x=5
Solve for x: 8^{x+1}*2^{2x}=4^{3x-1}
The solution is x=5