What is the answer to 10^{log_{10}(x^2)}=4 ?

The answer to 10^{log_{10}(x^2)}=4 is x=sqrt(10^{(2ln(2))/(ln(10)))},x=-sqrt(10^{(2ln(2))/(ln(10)))}

Solve for x: 10^{log_{10}(x^2)}=4

The solution is x=sqrt(10^{(2ln(2))/(ln(10)))},x=-sqrt(10^{(2ln(2))/(ln(10)))}

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1 0^{l o g_{10} (x^{2})} = 4

x = 1 0^{\frac{2 l n ( 2 )}{l n ( 10 )}}, x = - 1 0^{\frac{2 l n ( 2 )}{l n ( 10 )}}

Decimal Notation

x = 2, x = - 2

Solution steps

1 0^{l o g_{10} (x^{2})} = 4

Apply exponent rules

lo g_{10} (x^{2}) ln (10) = ln (4)

Solve

lo g_{10} (x^{2}) ln (10) = ln (4) : x = 1 0^{\frac{2 l n ( 2 )}{l n ( 10 )}}, x = - 1 0^{\frac{2 l n ( 2 )}{l n ( 10 )}}

x = 1 0^{\frac{2 l n ( 2 )}{l n ( 10 )}}, x = - 1 0^{\frac{2 l n ( 2 )}{l n ( 10 )}}

3^{x + 4} = 5^{x + 2}

9^{x} - 4 (3^{x}) + 3 = 0

e^{x} + 12 e^{- x} - 7 = 0

1 6^{2 x} = 8^{x - 1}

What is the answer to 10^{log_{10}(x^2)}=4 ?
The answer to 10^{log_{10}(x^2)}=4 is x=sqrt(10^{(2ln(2))/(ln(10)))},x=-sqrt(10^{(2ln(2))/(ln(10)))}
Solve for x: 10^{log_{10}(x^2)}=4
The solution is x=sqrt(10^{(2ln(2))/(ln(10)))},x=-sqrt(10^{(2ln(2))/(ln(10)))}