What is the answer to (5x-2)^{x-5}=(5x-2)^{2x+1} ?

The answer to (5x-2)^{x-5}=(5x-2)^{2x+1} is x= 3/5

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(5x-2)^{x-5}=(5x-2)^{2x+1}

(5 x - 2)^{x - 5} = (5 x - 2)^{2 x + 1}

x = \frac{3}{5}

Solution steps

(5 x - 2)^{x - 5} = (5 x - 2)^{2 x + 1}

Apply exponent rules

(x - 5) ln (5 x - 2) = (2 x + 1) ln (5 x - 2)

Solve

(x - 5) ln (5 x - 2) = (2 x + 1) ln (5 x - 2) : x = \frac{3}{5}

x = \frac{3}{5}

2. 5^{- 4 r} = 6.4

x^{l o g_{10} (x)} = 1 0^{8}

9^{x} + 9 = 10 \cdot 3^{x}

6^{3 x - 5} = 27

5 (2^{x - 3}) = 4 (3^{x + 4})

What is the answer to (5x-2)^{x-5}=(5x-2)^{2x+1} ?
The answer to (5x-2)^{x-5}=(5x-2)^{2x+1} is x= 3/5
Solve for x: (5x-2)^{x-5}=(5x-2)^{2x+1}
The solution is x= 3/5