What is the answer to 9*\sqrt[3x-1]{9}=9^x ?

The answer to 9*\sqrt[3x-1]{9}=9^x is x=0,x= 4/3

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9*\sqrt[3x-1]{9}=9^x

x = 0, x = \frac{4}{3}

Decimal Notation

x = 0, x = 1.33333 \dots

Solution steps

Apply exponent rules

\frac{1}{3 x - 1} + 1 = x

Solve

\frac{1}{3 x - 1} + 1 = x : x = 0, x = \frac{4}{3}

x = 0, x = \frac{4}{3}

4^{(2 x^{2} + x - 6)} = 1

t, a = p (1 + r)^{t}

(\frac{1}{16})^{x - 2} = 64

10 0^{x + 3} = \frac{1}{10}

What is the answer to 9*\sqrt[3x-1]{9}=9^x ?
The answer to 9*\sqrt[3x-1]{9}=9^x is x=0,x= 4/3
Solve for x: 9*\sqrt[3x-1]{9}=9^x
The solution is x=0,x= 4/3