What is the answer to (1/7)^{3a+3}=343^{a-1} ?

The answer to (1/7)^{3a+3}=343^{a-1} is a=0

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(1/7)^{3a+3}=343^{a-1}

(\frac{1}{7})^{3 a + 3} = 34 3^{a - 1}

a = 0

Solution steps

(\frac{1}{7})^{3 a + 3} = 34 3^{a - 1}

Apply exponent rules

- (3 a + 3) = 3 (a - 1)

Solve

- (3 a + 3) = 3 (a - 1) : a = 0

a = 0

x, 3^{x} = 7^{y}

70 \cdot e^{\frac{x}{4}} = 0.1

(3 x + 2)^{2 x + 5} = (3 x + 2)^{x - 2}

8^{x + 1} = 43

4^{2 x - 1} = 64

What is the answer to (1/7)^{3a+3}=343^{a-1} ?
The answer to (1/7)^{3a+3}=343^{a-1} is a=0
Solve for a: (1/7)^{3a+3}=343^{a-1}
The solution is a=0