What is the answer to 2*3^{(2x)/7}=30 ?

The answer to 2*3^{(2x)/7}=30 is x=(7ln(15))/(2ln(3))

Solve for x: 2*3^{(2x)/7}=30

The solution is x=(7ln(15))/(2ln(3))

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2 \cdot 3^{\frac{2 x}{7}} = 30

x = \frac{7 ln ( 15 )}{2 ln ( 3 )}

Solution steps

2 \cdot 3^{\frac{2 x}{7}} = 30

Divide both sides by

2

3^{\frac{2 x}{7}} = 15

Apply exponent rules

\frac{2 x}{7} ln (3) = ln (15)

Solve

\frac{2 x}{7} ln (3) = ln (15) : x = \frac{7 ln ( 15 )}{2 ln ( 3 )}

x = \frac{7 ln ( 15 )}{2 ln ( 3 )}

3^{x + 9} = 12

A = 50 e^{0.07 t}

1 6^{x + 1} = 8^{2 x + 1}

e^{x} - x^{3} = 0

What is the answer to 2*3^{(2x)/7}=30 ?
The answer to 2*3^{(2x)/7}=30 is x=(7ln(15))/(2ln(3))
Solve for x: 2*3^{(2x)/7}=30
The solution is x=(7ln(15))/(2ln(3))