What is the answer to 3(2^{(x)}+1)-2^{(x+2)}+5=0 ?

The answer to 3(2^{(x)}+1)-2^{(x+2)}+5=0 is x=3

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3(2^{(x)}+1)-2^{(x+2)}+5=0

3 (2^{(x)} + 1) - 2^{(x + 2)} + 5 = 0

x = 3

Solution steps

3 (2^{(x)} + 1) - 2^{(x + 2)} + 5 = 0

Factor

3 (2^{x} + 1) - 2^{x + 2} + 5 : 8 - 2^{x}

8 - 2^{x} = 0

Add

2^{x}

to both sides

8 - 2^{x} + 2^{x} = 0 + 2^{x}

Simplify

8 = 2^{x}

Apply exponent rules

3 = x

Switch sides

x = 3

3^{x - 4} = 1

2^{x - 5} = 3^{4 x + 1}

2^{x} = 5^{1 - x}

2^{3 x - 5} = 1024

e^{t^{2}} = 4

What is the answer to 3(2^{(x)}+1)-2^{(x+2)}+5=0 ?
The answer to 3(2^{(x)}+1)-2^{(x+2)}+5=0 is x=3
Solve for x: 3(2^{(x)}+1)-2^{(x+2)}+5=0
The solution is x=3