What is the answer to 2^{x+1}+6(2^{x-1})=12 ?

The answer to 2^{x+1}+6(2^{x-1})=12 is x=(ln(12/5))/(ln(2))

Solve for x: 2^{x+1}+6(2^{x-1})=12

The solution is x=(ln(12/5))/(ln(2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2^{x + 1} + 6 (2^{x - 1}) = 12

x = \frac{ln ( \frac{12}{5} )}{ln ( 2 )}

Decimal Notation

x = 1.26303 \dots

Solution steps

2^{x + 1} + 6 (2^{x - 1}) = 12

Factor

2^{x + 1} + 6 \cdot 2^{x - 1} : 5 \cdot 2^{x}

5 \cdot 2^{x} = 12

Divide both sides by

5

2^{x} = \frac{12}{5}

Apply exponent rules

x ln (2) = ln (\frac{12}{5})

Solve

x ln (2) = ln (\frac{12}{5}) : x = \frac{ln ( \frac{12}{5} )}{ln ( 2 )}

x = \frac{ln ( \frac{12}{5} )}{ln ( 2 )}

\frac{1}{36} = 6^{x - 3}

2^{y} = \frac{1}{8}

lo g_{6} (4 e^{y - 1}) = 2

0. 4^{x} = 0

3^{x} 2^{1 - x} = 10

What is the answer to 2^{x+1}+6(2^{x-1})=12 ?
The answer to 2^{x+1}+6(2^{x-1})=12 is x=(ln(12/5))/(ln(2))
Solve for x: 2^{x+1}+6(2^{x-1})=12
The solution is x=(ln(12/5))/(ln(2))