What is the answer to 3^{2(x+1)}-18*3^x+9=0 ?

The answer to 3^{2(x+1)}-18*3^x+9=0 is x=0

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3^{2(x+1)}-18*3^x+9=0

3^{2 (x + 1)} - 18 \cdot 3^{x} + 9 = 0

x = 0

Solution steps

3^{2 (x + 1)} - 18 \cdot 3^{x} + 9 = 0

Apply exponent rules

(3^{x})^{2} \cdot 3^{2} - 18 \cdot 3^{x} + 9 = 0

Rewrite the equation with

3^{x} = u

(u)^{2} \cdot 3^{2} - 18 u + 9 = 0

Solve

u^{2} \cdot 3^{2} - 18 u + 9 = 0 : u = 1

u = 1

Substitute back

u = 3^{x},

solve for

x

Solve

3^{x} = 1 : x = 0

x = 0

2^{x} - 2^{x - 2} = 3 (2^{13})

3 e^{2 x} = 4.2

4^{x} + 1 = 2^{x + 1}

5^{x} = 3^{x - 1}

What is the answer to 3^{2(x+1)}-18*3^x+9=0 ?
The answer to 3^{2(x+1)}-18*3^x+9=0 is x=0
Solve for x: 3^{2(x+1)}-18*3^x+9=0
The solution is x=0