What is the answer to (1/3)^{2x+5}=27^{1-x} ?

The answer to (1/3)^{2x+5}=27^{1-x} is x=8

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(1/3)^{2x+5}=27^{1-x}

(\frac{1}{3})^{2 x + 5} = 2 7^{1 - x}

x = 8

Solution steps

(\frac{1}{3})^{2 x + 5} = 2 7^{1 - x}

Apply exponent rules

- (2 x + 5) = 3 (1 - x)

Solve

- (2 x + 5) = 3 (1 - x) : x = 8

x = 8

x, 8 \cdot 2^{6} = 2^{x}

27 = 1 0^{x + 4}

2 (7^{y}) = 3 - 5 7^{y}

- 2 = 2^{x}

What is the answer to (1/3)^{2x+5}=27^{1-x} ?
The answer to (1/3)^{2x+5}=27^{1-x} is x=8
Solve for x: (1/3)^{2x+5}=27^{1-x}
The solution is x=8