What is the answer to 8^x=7 ?

The answer to 8^x=7 is x=(ln(7))/(3ln(2))

The solution is x=(ln(7))/(3ln(2))

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8^x=7

8^{x} = 7

x = \frac{ln ( 7 )}{3 ln ( 2 )}

Decimal Notation

x = 0.93578 \dots

Solution steps

8^{x} = 7

Apply exponent rules

x ln (8) = ln (7)

Solve

x ln (8) = ln (7) : x = \frac{ln ( 7 )}{3 ln ( 2 )}

x = \frac{ln ( 7 )}{3 ln ( 2 )}

e^{- x} = 0.2

9^{x} + 2 \cdot 3^{x + 1} - 1 = 0

2^{x + 1} = 6

\frac{1}{128} = 2^{5 x + 3}

9^{x + 1} 0.2 7^{x + 2} = 8 1^{x + 3}