What is the answer to 2^{x+1}=6 ?

The answer to 2^{x+1}=6 is x=(ln(6))/(ln(2))-1

Solve for x: 2^{x+1}=6

The solution is x=(ln(6))/(ln(2))-1

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2^{x + 1} = 6

x = \frac{ln ( 6 )}{ln ( 2 )} - 1

Decimal Notation

x = 1.58496 \dots

Solution steps

2^{x + 1} = 6

Apply exponent rules

(x + 1) ln (2) = ln (6)

Solve

(x + 1) ln (2) = ln (6) : x = \frac{ln ( 6 )}{ln ( 2 )} - 1

x = \frac{ln ( 6 )}{ln ( 2 )} - 1

\frac{1}{128} = 2^{5 x + 3}

9^{x + 1} 0.2 7^{x + 2} = 8 1^{x + 3}

7^{x} + 7^{x + 2} = - 2051 + 7^{x + 3}

2 7^{x} (9^{2 x - 1}) = 3^{x + 4}

2^{8 x + 3} = 2

What is the answer to 2^{x+1}=6 ?
The answer to 2^{x+1}=6 is x=(ln(6))/(ln(2))-1
Solve for x: 2^{x+1}=6
The solution is x=(ln(6))/(ln(2))-1