What is the answer to 9^{x+1}0.27^{x+2}=81^{x+3} ?

The answer to 9^{x+1}0.27^{x+2}=81^{x+3} is x=(12ln(3)-ln(0.6561))/(ln(2.43)-4ln(3))

Solve for x: 9^{x+1}0.27^{x+2}=81^{x+3}

The solution is x=(12ln(3)-ln(0.6561))/(ln(2.43)-4ln(3))

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9^{x + 1} 0.2 7^{x + 2} = 8 1^{x + 3}

x = \frac{12 ln ( 3 ) - ln ( 0.6561 )}{ln ( 2.43 ) - 4 ln ( 3 )}

Decimal Notation

x = - 3.87981 \dots

Solution steps

9^{x + 1} \cdot 0.2 7^{x + 2} = 8 1^{x + 3}

Apply exponent rules

(x + 1) ln (2.43) + ln (0.2 7^{1}) = (x + 3) ln (81)

Solve

(x + 1) ln (2.43) + ln (0.2 7^{1}) = (x + 3) ln (81) : x = \frac{12 ln ( 3 ) - ln ( 0.6561 )}{ln ( 2.43 ) - 4 ln ( 3 )}

x = \frac{12 ln ( 3 ) - ln ( 0.6561 )}{ln ( 2.43 ) - 4 ln ( 3 )}

7^{x} + 7^{x + 2} = - 2051 + 7^{x + 3}

2 7^{x} (9^{2 x - 1}) = 3^{x + 4}

2^{8 x + 3} = 2

\frac{27}{9 ^{x}} = 3^{x - 1}

3 6^{2 x - 7} = 6^{x - 5}

What is the answer to 9^{x+1}0.27^{x+2}=81^{x+3} ?
The answer to 9^{x+1}0.27^{x+2}=81^{x+3} is x=(12ln(3)-ln(0.6561))/(ln(2.43)-4ln(3))
Solve for x: 9^{x+1}0.27^{x+2}=81^{x+3}
The solution is x=(12ln(3)-ln(0.6561))/(ln(2.43)-4ln(3))