What are the solutions to the equation 1^2+x^2=sqrt(2)^2 ?

The solutions to the equation 1^2+x^2=sqrt(2)^2 are x=1,x=-1

Find the zeros of 1^2+x^2=sqrt(2)^2

The zeros of 1^2+x^2=sqrt(2)^2 are x=1,x=-1

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1^{2} + x^{2} = 2^{2}

x = 1, x = - 1

Solution steps

1^{2} + x^{2} = (2)^{2}

Move

1^{2}

to the right side

x^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1, x = - 1

1 = 1

- 1 = - 1

x = 1, x = - 1

x^{2} - 7 x + 18 = 0

\frac{x ^{14}}{x ^{7}}

x^{2} + 12 x + 36 = 0

15 = π r + 2 r

x^{2} - 121 < 0

What are the solutions to the equation 1^2+x^2=sqrt(2)^2 ?
The solutions to the equation 1^2+x^2=sqrt(2)^2 are x=1,x=-1
Find the zeros of 1^2+x^2=sqrt(2)^2
The zeros of 1^2+x^2=sqrt(2)^2 are x=1,x=-1