What is the answer to 3^{x+2}=6 ?

The answer to 3^{x+2}=6 is x=(ln(6))/(ln(3))-2

Solve for x: 3^{x+2}=6

The solution is x=(ln(6))/(ln(3))-2

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3^{x + 2} = 6

x = \frac{ln ( 6 )}{ln ( 3 )} - 2

Decimal Notation

x = - 0.36907 \dots

Solution steps

3^{x + 2} = 6

Apply exponent rules

(x + 2) ln (3) = ln (6)

Solve

(x + 2) ln (3) = ln (6) : x = \frac{ln ( 6 )}{ln ( 3 )} - 2

x = \frac{ln ( 6 )}{ln ( 3 )} - 2

3 2^{x - 1} = 64

\frac{1}{125} = 5^{n}

5^{x^{2} + 2 x + 5} = 5^{- 3 x - 1}

4^{y + 1} = 8^{2 y - 1}

e^{x^{2} - x} = e^{2}

What is the answer to 3^{x+2}=6 ?
The answer to 3^{x+2}=6 is x=(ln(6))/(ln(3))-2
Solve for x: 3^{x+2}=6
The solution is x=(ln(6))/(ln(3))-2