What is the answer to 5^{x^2+2x+5}=5^{-3x-1} ?

The answer to 5^{x^2+2x+5}=5^{-3x-1} is x=-2,x=-3

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5^{x^2+2x+5}=5^{-3x-1}

5^{x^{2} + 2 x + 5} = 5^{- 3 x - 1}

x = - 2, x = - 3

Solution steps

5^{x^{2} + 2 x + 5} = 5^{- 3 x - 1}

Apply exponent rules

x^{2} + 2 x + 5 = - 3 x - 1

Solve

x^{2} + 2 x + 5 = - 3 x - 1 : x = - 2, x = - 3

x = - 2, x = - 3

4^{y + 1} = 8^{2 y - 1}

e^{x^{2} - x} = e^{2}

e^{2 x + 3} = 5

3^{2 x - 2} = 9^{3 x + 2}

2^{2 x} \cdot 5^{x} = 8000

What is the answer to 5^{x^2+2x+5}=5^{-3x-1} ?
The answer to 5^{x^2+2x+5}=5^{-3x-1} is x=-2,x=-3
Solve for x: 5^{x^2+2x+5}=5^{-3x-1}
The solution is x=-2,x=-3