What is the answer to 7^{x-1}=5 ?

The answer to 7^{x-1}=5 is x=(ln(5))/(ln(7))+1

Solve for x: 7^{x-1}=5

The solution is x=(ln(5))/(ln(7))+1

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7^{x - 1} = 5

x = \frac{ln ( 5 )}{ln ( 7 )} + 1

Decimal Notation

x = 1.82708 \dots

Solution steps

7^{x - 1} = 5

Apply exponent rules

(x - 1) ln (7) = ln (5)

Solve

(x - 1) ln (7) = ln (5) : x = \frac{ln ( 5 )}{ln ( 7 )} + 1

x = \frac{ln ( 5 )}{ln ( 7 )} + 1

1 2^{x^{2} + 2 x + 3} = 1728

2^{2 x} = \frac{1}{8}

e^{- x} + 2 x - 1 = 0

2^{8^{x - 2}} = 4^{4^{x - 1}}

4^{2 x + 1} - 65 (4^{x}) + 16 = 0

What is the answer to 7^{x-1}=5 ?
The answer to 7^{x-1}=5 is x=(ln(5))/(ln(7))+1
Solve for x: 7^{x-1}=5
The solution is x=(ln(5))/(ln(7))+1