What is the answer to 2^x+3^x=0 ?

The answer to 2^x+3^x=0 is x=(Undefined)/(ln(2))

Solve for x: 2^x+3^x=0

The solution is x=(Undefined)/(ln(2))

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2^{x} + 3^{x} = 0

x = \frac{Undefined}{ln ( 2 )}

Solution steps

2^{x} + 3^{x} = 0

Subtract

3^{x}

from both sides

2^{x} + 3^{x} - 3^{x} = 0 - 3^{x}

Simplify

2^{x} = - 3^{x}

Apply exponent rules

x ln (2) = ln (- 1) + x ln (3)

Solve

x ln (2) = ln (- 1) + x ln (3) : x = \frac{Undefined}{ln ( 2 )}

x = \frac{Undefined}{ln ( 2 )}

1 8^{x^{2} + 4 x + 4} = 1 8^{9 x + 18}

9^{2 x - 1} = 2 7^{x}

89 = 1 5^{x}

3^{x - 1} = 20

What is the answer to 2^x+3^x=0 ?
The answer to 2^x+3^x=0 is x=(Undefined)/(ln(2))
Solve for x: 2^x+3^x=0
The solution is x=(Undefined)/(ln(2))