What is the answer to 9*\sqrt[3x+1]{9}=9^x ?

The answer to 9*\sqrt[3x+1]{9}=9^x is x=(1+sqrt(7))/3 ,x=(1-sqrt(7))/3

Solve for x: 9*\sqrt[3x+1]{9}=9^x

The solution is x=(1+sqrt(7))/3 ,x=(1-sqrt(7))/3

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x = \frac{1 + 7}{3}, x = \frac{1 - 7}{3}

Decimal Notation

x = 1.21525 \dots, x = - 0.54858 \dots

Solution steps

Apply exponent rules

\frac{1}{3 x + 1} + 1 = x

Solve

\frac{1}{3 x + 1} + 1 = x : x = \frac{1 + 7}{3}, x = \frac{1 - 7}{3}

x = \frac{1 + 7}{3}, x = \frac{1 - 7}{3}

1 8^{x^{2} + 4 x + 4} = 1 8^{9 x + 18}

9^{2 x - 1} = 2 7^{x}

89 = 1 5^{x}

3^{x - 1} = 20

3^{x - 4} = 2

What is the answer to 9*\sqrt[3x+1]{9}=9^x ?
The answer to 9*\sqrt[3x+1]{9}=9^x is x=(1+sqrt(7))/3 ,x=(1-sqrt(7))/3
Solve for x: 9*\sqrt[3x+1]{9}=9^x
The solution is x=(1+sqrt(7))/3 ,x=(1-sqrt(7))/3