What is the answer to 2^{3x-5}=3^{5x+4} ?

The answer to 2^{3x-5}=3^{5x+4} is x=(ln(2592))/(3ln(2)-5ln(3))

Solve for x: 2^{3x-5}=3^{5x+4}

The solution is x=(ln(2592))/(3ln(2)-5ln(3))

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2^{3 x - 5} = 3^{5 x + 4}

x = \frac{ln ( 2592 )}{3 ln ( 2 ) - 5 ln ( 3 )}

Solution steps

2^{3 x - 5} = 3^{5 x + 4}

Apply exponent rules

(3 x - 5) ln (2) = (5 x + 4) ln (3)

Solve

(3 x - 5) ln (2) = (5 x + 4) ln (3) : x = \frac{ln ( 2592 )}{3 ln ( 2 ) - 5 ln ( 3 )}

x = \frac{ln ( 2592 )}{3 ln ( 2 ) - 5 ln ( 3 )}

96 = 2^{x}

3^{x^{2} + 2 x + 6} = 2 7^{x + 4}

1 3^{x} = 21 3^{- x}

(27)^{x^{2}} = \frac{1}{9 ^{x}}

2^{x} + 2^{x + 2} = \frac{5}{8 ^{b}}

What is the answer to 2^{3x-5}=3^{5x+4} ?
The answer to 2^{3x-5}=3^{5x+4} is x=(ln(2592))/(3ln(2)-5ln(3))
Solve for x: 2^{3x-5}=3^{5x+4}
The solution is x=(ln(2592))/(3ln(2)-5ln(3))