What is the answer to 9^{1-2x}= 1/(27^{x-4)} ?

The answer to 9^{1-2x}= 1/(27^{x-4)} is x=-10

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9^{1-2x}= 1/(27^{x-4)}

9^{1 - 2 x} = \frac{1}{2 7 ^{x - 4}}

x = - 10

Solution steps

9^{1 - 2 x} = \frac{1}{2 7 ^{x - 4}}

Apply exponent rules

2 (1 - 2 x) = 3 (- x + 4)

Solve

2 (1 - 2 x) = 3 (- x + 4) : x = - 10

x = - 10

Verify Solutions:

x = - 10

True

The solution is

x = - 10

5^{3 y} = 64

5 ln (4 - 3^{x}) = 6

y, - 2^{y} + 5 = 7 x

5^{2 x + 3} = 125

57 = 2 5^{x}

What is the answer to 9^{1-2x}= 1/(27^{x-4)} ?
The answer to 9^{1-2x}= 1/(27^{x-4)} is x=-10
Solve for x: 9^{1-2x}= 1/(27^{x-4)}
The solution is x=-10