What is the answer to 2^{5x+3}=3^{2x+1} ?

The answer to 2^{5x+3}=3^{2x+1} is x=(ln(3)-3ln(2))/(5ln(2)-2ln(3))

Solve for x: 2^{5x+3}=3^{2x+1}

The solution is x=(ln(3)-3ln(2))/(5ln(2)-2ln(3))

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2^{5 x + 3} = 3^{2 x + 1}

x = \frac{ln ( 3 ) - 3 ln ( 2 )}{5 ln ( 2 ) - 2 ln ( 3 )}

Decimal Notation

x = - 0.77321 \dots

Solution steps

2^{5 x + 3} = 3^{2 x + 1}

Apply exponent rules

(5 x + 3) ln (2) = (2 x + 1) ln (3)

Solve

(5 x + 3) ln (2) = (2 x + 1) ln (3) : x = \frac{ln ( 3 ) - 3 ln ( 2 )}{5 ln ( 2 ) - 2 ln ( 3 )}

x = \frac{ln ( 3 ) - 3 ln ( 2 )}{5 ln ( 2 ) - 2 ln ( 3 )}

3^{x} 2^{3 x} = 4

6^{x - 3} = 17

(\frac{1}{2})^{x} = \frac{1}{8}

3^{x + 1} = 3^{x} + 18

3^{5 x + 2} = 9^{x + 4}

What is the answer to 2^{5x+3}=3^{2x+1} ?
The answer to 2^{5x+3}=3^{2x+1} is x=(ln(3)-3ln(2))/(5ln(2)-2ln(3))
Solve for x: 2^{5x+3}=3^{2x+1}
The solution is x=(ln(3)-3ln(2))/(5ln(2)-2ln(3))