What is the answer to 2(5+3^{x+1})=100 ?

The answer to 2(5+3^{x+1})=100 is x=(ln(45))/(ln(3))-1

Solve for x: 2(5+3^{x+1})=100

The solution is x=(ln(45))/(ln(3))-1

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2 (5 + 3^{x + 1}) = 100

x = \frac{ln ( 45 )}{ln ( 3 )} - 1

Solution steps

2 (5 + 3^{x + 1}) = 100

Divide both sides by

2

5 + 3^{x + 1} = 50

Move

5

to the right side

3^{x + 1} = 45

Apply exponent rules

(x + 1) ln (3) = ln (45)

Solve

(x + 1) ln (3) = ln (45) : x = \frac{ln ( 45 )}{ln ( 3 )} - 1

x = \frac{ln ( 45 )}{ln ( 3 )} - 1

2^{x + 1} = 3 x

10 x - e^{- x} = 0

8^{4 x - 3} = (\frac{1}{16})^{x + 1}

4 e^{- x} = 3 e^{x} + 4

1 0^{x} = (1 0^{- 14}) (1 0^{2})

What is the answer to 2(5+3^{x+1})=100 ?
The answer to 2(5+3^{x+1})=100 is x=(ln(45))/(ln(3))-1
Solve for x: 2(5+3^{x+1})=100
The solution is x=(ln(45))/(ln(3))-1