What is the answer to 9^{3x-4}= 1/(81^{2x-5)} ?

The answer to 9^{3x-4}= 1/(81^{2x-5)} is x=2

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9^{3x-4}= 1/(81^{2x-5)}

9^{3 x - 4} = \frac{1}{8 1 ^{2 x - 5}}

x = 2

Solution steps

9^{3 x - 4} = \frac{1}{8 1 ^{2 x - 5}}

Apply exponent rules

3 x - 4 = 2 (- 2 x + 5)

Solve

3 x - 4 = 2 (- 2 x + 5) : x = 2

x = 2

Verify Solutions:

x = 2

True

The solution is

x = 2

3^{x^{2}} = 7

9 e^{x} = 107

2^{b} = 7

77 = 2 3^{x}

3^{2 x} + 2 \cdot 3^{x} + 1 = 0

What is the answer to 9^{3x-4}= 1/(81^{2x-5)} ?
The answer to 9^{3x-4}= 1/(81^{2x-5)} is x=2
Solve for x: 9^{3x-4}= 1/(81^{2x-5)}
The solution is x=2