What is the answer to 3^x5^{x+1}=12^{2x-1} ?

The answer to 3^x5^{x+1}=12^{2x-1} is x=(ln(60))/(ln(48/5))

Solve for x: 3^x5^{x+1}=12^{2x-1}

The solution is x=(ln(60))/(ln(48/5))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3^{x} 5^{x + 1} = 1 2^{2 x - 1}

x = \frac{ln ( 60 )}{ln ( \frac{48}{5} )}

Decimal Notation

x = 1.81024 \dots

Solution steps

3^{x} \cdot 5^{x + 1} = 1 2^{2 x - 1}

Apply exponent rules

x ln (15) + ln (5^{1}) = (2 x - 1) ln (12)

Solve

x ln (15) + ln (5^{1}) = (2 x - 1) ln (12) : x = \frac{ln ( 60 )}{ln ( \frac{48}{5} )}

x = \frac{ln ( 60 )}{ln ( \frac{48}{5} )}

1 = e^{\frac{- 1}{3} (1^{3} + 3 + 3 c)}

2^{x^{2} - 14} = \frac{1}{1024}

3^{2 x - 1} x^{9} = 3^{x + 2} x^{27}

x, 8^{y} = 4^{2 x + 1}

e^{4 x} + 2 e^{2 x} - 8 = 0

What is the answer to 3^x5^{x+1}=12^{2x-1} ?
The answer to 3^x5^{x+1}=12^{2x-1} is x=(ln(60))/(ln(48/5))
Solve for x: 3^x5^{x+1}=12^{2x-1}
The solution is x=(ln(60))/(ln(48/5))