What is the answer to 8^{3x+1}=128^{x-2} ?

The answer to 8^{3x+1}=128^{x-2} is x=-17/2

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8^{3x+1}=128^{x-2}

8^{3 x + 1} = 12 8^{x - 2}

x = - \frac{17}{2}

Solution steps

8^{3 x + 1} = 12 8^{x - 2}

Apply exponent rules

3 (3 x + 1) = 7 (x - 2)

Solve

3 (3 x + 1) = 7 (x - 2) : x = - \frac{17}{2}

x = - \frac{17}{2}

7^{x - 4} = 7^{8}

2^{3 - 8 w} = 18

1 0^{3 x - 1} = 1

8^{x + 1} - 8^{x - 1} = 20

71 = 2 1^{x}

What is the answer to 8^{3x+1}=128^{x-2} ?
The answer to 8^{3x+1}=128^{x-2} is x=-17/2
Solve for x: 8^{3x+1}=128^{x-2}
The solution is x=-17/2