What is the answer to 8^{x+1}-8^{x-1}=20 ?

The answer to 8^{x+1}-8^{x-1}=20 is x=(ln(20/63))/(3ln(2))+1

Solve for x: 8^{x+1}-8^{x-1}=20

The solution is x=(ln(20/63))/(3ln(2))+1

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8^{x + 1} - 8^{x - 1} = 20

x = \frac{ln ( \frac{20}{63} )}{3 ln ( 2 )} + 1

Decimal Notation

x = 0.44821 \dots

Solution steps

8^{x + 1} - 8^{x - 1} = 20

Factor

8^{x + 1} - 8^{x - 1} : 63 \cdot 8^{x - 1}

63 \cdot 8^{x - 1} = 20

Divide both sides by

63

8^{x - 1} = \frac{20}{63}

Apply exponent rules

(x - 1) ln (8) = ln (\frac{20}{63})

Solve

(x - 1) ln (8) = ln (\frac{20}{63}) : x = \frac{ln ( \frac{20}{63} )}{3 ln ( 2 )} + 1

x = \frac{ln ( \frac{20}{63} )}{3 ln ( 2 )} + 1

71 = 2 1^{x}

5^{2 x} = 5^{x} + 30

300 = 1500 - 1500 (0.9)^{t}

2 \cdot 7^{- 6 x} = 36

e^{2 x} - 1 = 0

What is the answer to 8^{x+1}-8^{x-1}=20 ?
The answer to 8^{x+1}-8^{x-1}=20 is x=(ln(20/63))/(3ln(2))+1
Solve for x: 8^{x+1}-8^{x-1}=20
The solution is x=(ln(20/63))/(3ln(2))+1