What is the answer to 4^{x-5}=(1/8)^{8-x} ?

The answer to 4^{x-5}=(1/8)^{8-x} is x=14

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4^{x-5}=(1/8)^{8-x}

4^{x - 5} = (\frac{1}{8})^{8 - x}

x = 14

Solution steps

4^{x - 5} = (\frac{1}{8})^{8 - x}

Apply exponent rules

2 (x - 5) = - 3 (8 - x)

Solve

2 (x - 5) = - 3 (8 - x) : x = 14

x = 14

\frac{1}{16} = 6 4^{4 x - 3}

e^{x} (2 x + x^{2}) = 0

3^{2 x^{2} + 3 x - 2} = 1

8 1^{x^{2} - 1} = 2 7^{- (7 - 5 x)}

6 (4^{x}) - 11 (2^{x}) + 4 = 0

What is the answer to 4^{x-5}=(1/8)^{8-x} ?
The answer to 4^{x-5}=(1/8)^{8-x} is x=14
Solve for x: 4^{x-5}=(1/8)^{8-x}
The solution is x=14