What is the answer to 2^{x+2}+2^{x-1}-2^{x-3}=70 ?

The answer to 2^{x+2}+2^{x-1}-2^{x-3}=70 is x=4

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2^{x+2}+2^{x-1}-2^{x-3}=70

2^{x + 2} + 2^{x - 1} - 2^{x - 3} = 70

x = 4

Solution steps

2^{x + 2} + 2^{x - 1} - 2^{x - 3} = 70

Factor

2^{x + 2} + 2^{x - 1} - 2^{x - 3} : 35 \cdot 2^{x - 3}

35 \cdot 2^{x - 3} = 70

Divide both sides by

35

2^{x - 3} = 2

Apply exponent rules

x - 3 = 1

Solve

x - 3 = 1 : x = 4

x = 4

n, p = \frac{1}{1 0 ^{n}}

2^{2 x + 18} = 3^{x - 12}

e^{x} = 17.8

x e^{x} - e^{x} = 0

6 = e^{x}

What is the answer to 2^{x+2}+2^{x-1}-2^{x-3}=70 ?
The answer to 2^{x+2}+2^{x-1}-2^{x-3}=70 is x=4
Solve for x: 2^{x+2}+2^{x-1}-2^{x-3}=70
The solution is x=4