What is the answer to 4^x5^{x+1}=12^{2x-1} ?

The answer to 4^x5^{x+1}=12^{2x-1} is x=(ln(60))/(ln(36/5))

Solve for x: 4^x5^{x+1}=12^{2x-1}

The solution is x=(ln(60))/(ln(36/5))

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4^{x} 5^{x + 1} = 1 2^{2 x - 1}

x = \frac{ln ( 60 )}{ln ( \frac{36}{5} )}

Decimal Notation

x = 2.07405 \dots

Solution steps

4^{x} \cdot 5^{x + 1} = 1 2^{2 x - 1}

Apply exponent rules

x ln (20) + ln (5^{1}) = (2 x - 1) ln (12)

Solve

x ln (20) + ln (5^{1}) = (2 x - 1) ln (12) : x = \frac{ln ( 60 )}{ln ( \frac{36}{5} )}

x = \frac{ln ( 60 )}{ln ( \frac{36}{5} )}

(x + 2)^{x + 4} = (x + 2)^{x^{2} + 3 x + 1}

25.4 = 2.2 1^{x^{365}}

2^{x} = x + 2

What is the answer to 4^x5^{x+1}=12^{2x-1} ?
The answer to 4^x5^{x+1}=12^{2x-1} is x=(ln(60))/(ln(36/5))
Solve for x: 4^x5^{x+1}=12^{2x-1}
The solution is x=(ln(60))/(ln(36/5))