What is the answer to 440=27.5(\sqrt[12]{2})^{n-1} ?

The answer to 440=27.5(\sqrt[12]{2})^{n-1} is n=49

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440=27.5(\sqrt[12]{2})^{n-1}

n = 49

Solution steps

Apply exponent rules

\frac{1}{12} (n - 1) = 4

Solve

\frac{1}{12} (n - 1) = 4 : n = 49

n = 49

(x + 2)^{x + 4} = (x + 2)^{x^{2} + 3 x + 1}

25.4 = 2.2 1^{x^{365}}

2^{x} = x + 2

15 \cdot 5^{x} = 53 \cdot 2^{x}

What is the answer to 440=27.5(\sqrt[12]{2})^{n-1} ?
The answer to 440=27.5(\sqrt[12]{2})^{n-1} is n=49
Solve for n: 440=27.5(\sqrt[12]{2})^{n-1}
The solution is n=49