What is the answer to solvefor x,f=(2^x)/m ?

The answer to solvefor x,f=(2^x)/m is x=(ln(fm))/(ln(2))

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solvefor x,f=(2^x)/m

solve for

x, f = \frac{2 ^{x}}{m}

x = \frac{ln ( f m )}{ln ( 2 )}

Solution steps

f = \frac{2 ^{x}}{m}

Multiply both sides by

m

f m = \frac{2 ^{x}}{m} m

Simplify

f m = 2^{x}

Apply exponent rules

ln (f m) = x ln (2)

Solve

ln (f m) = x ln (2) : x = \frac{ln ( f m )}{ln ( 2 )}

x = \frac{ln ( f m )}{ln ( 2 )}

2^{x - 5} = 5

2^{x - 5} = 4

x, - e^{- y} = e^{x} + c

1 0^{2 x + 3} = 5

2^{n - 6} = 8^{2 - n}

What is the answer to solvefor x,f=(2^x)/m ?
The answer to solvefor x,f=(2^x)/m is x=(ln(fm))/(ln(2))